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3/5c+6/5=2c+3+2/5c
We move all terms to the left:
3/5c+6/5-(2c+3+2/5c)=0
Domain of the equation: 5c!=0
c!=0/5
c!=0
c∈R
Domain of the equation: 5c)!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
3/5c-(2c+2/5c+3)+6/5=0
We get rid of parentheses
3/5c-2c-2/5c-3+6/5=0
We calculate fractions
-2c-3=0
We move all terms containing c to the left, all other terms to the right
-2c=3
c=3/-2
c=-1+1/2
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