3/5f+24=4+6/10f

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Solution for 3/5f+24=4+6/10f equation: 



3/5f+24=4+6/10f

We move all terms to the left:

3/5f+24-(4+6/10f)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R





Domain of the equation: 10f)!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

3/5f-(6/10f+4)+24=0

We get rid of parentheses

3/5f-6/10f-4+24=0

We calculate fractions


30f/50f^2+(-30f)/50f^2-4+24=0

We add all the numbers together, and all the variables

30f/50f^2+(-30f)/50f^2+20=0

We multiply all the terms by the denominator


30f+(-30f)+20*50f^2=0

Wy multiply elements

1000f^2+30f+(-30f)=0

We get rid of parentheses

1000f^2+30f-30f=0

We add all the numbers together, and all the variables

1000f^2=0

a = 1000; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1000·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{0}{2000}=0$

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