3/5k-(k+1/5)=1/25(k+1)

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Solution for 3/5k-(k+1/5)=1/25(k+1) equation: 



3/5k-(k+1/5)=1/25(k+1)

We move all terms to the left:

3/5k-(k+1/5)-(1/25(k+1))=0



Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R





Domain of the equation: 25(k+1))!=0

k∈R



We add all the numbers together, and all the variables

3/5k-(+k+1/5)-(1/25(k+1))=0

We get rid of parentheses

3/5k-k-(1/25(k+1))-1/5=0

We calculate fractions


-k+(75kk/(625k^2k+(-(1*5k*5)/(625k^2k+(-25kk/(625k^2k=0

We can not solve this equation

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