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3/5m-1-2m=10=18
We move all terms to the left:
3/5m-1-2m-(10)=0
Domain of the equation: 5m!=0We add all the numbers together, and all the variables
m!=0/5
m!=0
m∈R
-2m+3/5m-11=0
We multiply all the terms by the denominator
-2m*5m-11*5m+3=0
Wy multiply elements
-10m^2-55m+3=0
a = -10; b = -55; c = +3;
Δ = b2-4ac
Δ = -552-4·(-10)·3
Δ = 3145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{3145}}{2*-10}=\frac{55-\sqrt{3145}}{-20} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{3145}}{2*-10}=\frac{55+\sqrt{3145}}{-20} $
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