3/5p+1/5(40-p)=0p=10

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Solution for 3/5p+1/5(40-p)=0p=10 equation: 



3/5p+1/5(40-p)=0p=10

We move all terms to the left:

3/5p+1/5(40-p)-(0p)=0



Domain of the equation: 5p!=0

p!=0/5

p!=0

p∈R





Domain of the equation: 5(40-p)!=0

p∈R



We add all the numbers together, and all the variables

3/5p+1/5(-1p+40)-0p=0

We add all the numbers together, and all the variables

-1p+3/5p+1/5(-1p+40)=0

We calculate fractions


-1p+(15p(-)/(25p^2(-)+5p/(25p^2(-)=0



We calculate terms in parentheses: +(15p(-)/(25p^2(-)+5p/(25p^2(-), so:

15p(-)/(25p^2(-)+5p/(25p^2(-

We can not solve this equation

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