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3/5p+1/5=(40-p)=0
We move all terms to the left:
3/5p+1/5-((40-p))=0
Domain of the equation: 5p!=0We add all the numbers together, and all the variables
p!=0/5
p!=0
p∈R
3/5p-((-1p+40))+1/5=0
We calculate fractions
-((-1p+40))=0
We calculate terms in parentheses: -((-1p+40)), so:We get rid of parentheses
(-1p+40)
We get rid of parentheses
-1p+40
Back to the equation:
-(-1p+40)
1p-40=0
We add all the numbers together, and all the variables
p-40=0
We move all terms containing p to the left, all other terms to the right
p=40
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