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3/5p=1/5(40-p+0)
We move all terms to the left:
3/5p-(1/5(40-p+0))=0
Domain of the equation: 5p!=0
p!=0/5
p!=0
p∈R
Domain of the equation: 5(40-p+0))!=0We add all the numbers together, and all the variables
p∈R
3/5p-(1/5(-1p+40))=0
We calculate fractions
(15p(-)/(25p^2(-)+(-(1*5p)/(25p^2(-)=0
We calculate terms in parentheses: +(15p(-)/(25p^2(-)+(-(1*5p)/(25p^2(-), so:
15p(-)/(25p^2(-)+(-(1*5p)/(25p^2(-
We can not solve this equation
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