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3/5w+9=3/4w
We move all terms to the left:
3/5w+9-(3/4w)=0
Domain of the equation: 5w!=0
w!=0/5
w!=0
w∈R
Domain of the equation: 4w)!=0We add all the numbers together, and all the variables
w!=0/1
w!=0
w∈R
3/5w-(+3/4w)+9=0
We get rid of parentheses
3/5w-3/4w+9=0
We calculate fractions
12w/20w^2+(-15w)/20w^2+9=0
We multiply all the terms by the denominator
12w+(-15w)+9*20w^2=0
Wy multiply elements
180w^2+12w+(-15w)=0
We get rid of parentheses
180w^2+12w-15w=0
We add all the numbers together, and all the variables
180w^2-3w=0
a = 180; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·180·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*180}=\frac{0}{360} =0 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*180}=\frac{6}{360} =1/60 $
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