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3/5x+1/5(40-x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5(40-x)!=0We add all the numbers together, and all the variables
x∈R
3/5x+1/5(-1x+40)=0
We calculate fractions
(15x(-)/(25x^2(-)+5x/(25x^2(-)=0
We calculate terms in parentheses: +(15x(-)/(25x^2(-)+5x/(25x^2(-), so:
15x(-)/(25x^2(-)+5x/(25x^2(-
We can not solve this equation
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