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3/5x+11=-9/5x+3
We move all terms to the left:
3/5x+11-(-9/5x+3)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x+3)!=0We get rid of parentheses
x∈R
3/5x+9/5x-3+11=0
We multiply all the terms by the denominator
-3*5x+11*5x+3+9=0
We add all the numbers together, and all the variables
-3*5x+11*5x+12=0
Wy multiply elements
-15x+55x+12=0
We add all the numbers together, and all the variables
40x+12=0
We move all terms containing x to the left, all other terms to the right
40x=-12
x=-12/40
x=-3/10
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