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3/5x+11=49
We move all terms to the left:
3/5x+11-(49)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-38=0
We multiply all the terms by the denominator
-38*5x+3=0
Wy multiply elements
-190x+3=0
We move all terms containing x to the left, all other terms to the right
-190x=-3
x=-3/-190
x=3/190
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