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3/5x+2/4x-2+90=180
We move all terms to the left:
3/5x+2/4x-2+90-(180)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
3/5x+2/4x-92=0
We calculate fractions
12x/20x^2+10x/20x^2-92=0
We multiply all the terms by the denominator
12x+10x-92*20x^2=0
We add all the numbers together, and all the variables
22x-92*20x^2=0
Wy multiply elements
-1840x^2+22x=0
a = -1840; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-1840)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-1840}=\frac{-44}{-3680} =11/920 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-1840}=\frac{0}{-3680} =0 $
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