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3/5x+2=3x
We move all terms to the left:
3/5x+2-(3x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-3x+3/5x+2=0
We multiply all the terms by the denominator
-3x*5x+2*5x+3=0
Wy multiply elements
-15x^2+10x+3=0
a = -15; b = 10; c = +3;
Δ = b2-4ac
Δ = 102-4·(-15)·3
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{70}}{2*-15}=\frac{-10-2\sqrt{70}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{70}}{2*-15}=\frac{-10+2\sqrt{70}}{-30} $
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