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3/5x+2x+18=4x-1
We move all terms to the left:
3/5x+2x+18-(4x-1)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2x+3/5x-(4x-1)+18=0
We get rid of parentheses
2x+3/5x-4x+1+18=0
We multiply all the terms by the denominator
2x*5x-4x*5x+1*5x+18*5x+3=0
Wy multiply elements
10x^2-20x^2+5x+90x+3=0
We add all the numbers together, and all the variables
-10x^2+95x+3=0
a = -10; b = 95; c = +3;
Δ = b2-4ac
Δ = 952-4·(-10)·3
Δ = 9145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-\sqrt{9145}}{2*-10}=\frac{-95-\sqrt{9145}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+\sqrt{9145}}{2*-10}=\frac{-95+\sqrt{9145}}{-20} $
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