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3/5x+40=150
We move all terms to the left:
3/5x+40-(150)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-110=0
We multiply all the terms by the denominator
-110*5x+3=0
Wy multiply elements
-550x+3=0
We move all terms containing x to the left, all other terms to the right
-550x=-3
x=-3/-550
x=3/550
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