3/5x+4=-1/3x+7

Solution for 3/5x+4=-1/3x+7 equation:

3/5x+4=-1/3x+7

We move all terms to the left:

3/5x+4-(-1/3x+7)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 3x+7)!=0

x∈R


We get rid of parentheses

3/5x+1/3x-7+4=0

We calculate fractions


9x/15x^2+5x/15x^2-7+4=0

We add all the numbers together, and all the variables

9x/15x^2+5x/15x^2-3=0

We multiply all the terms by the denominator


9x+5x-3*15x^2=0

We add all the numbers together, and all the variables

14x-3*15x^2=0

Wy multiply elements

-45x^2+14x=0

a = -45; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-45)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-45}=\frac{-28}{-90}
=14/45
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-45}=\frac{0}{-90}
=0
$