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3/5x+4=x+5
We move all terms to the left:
3/5x+4-(x+5)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3/5x-x-5+4=0
We multiply all the terms by the denominator
-x*5x-5*5x+4*5x+3=0
Wy multiply elements
-5x^2-25x+20x+3=0
We add all the numbers together, and all the variables
-5x^2-5x+3=0
a = -5; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·(-5)·3
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{85}}{2*-5}=\frac{5-\sqrt{85}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{85}}{2*-5}=\frac{5+\sqrt{85}}{-10} $
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