3/5x+5/2=1/10x+x

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Solution for 3/5x+5/2=1/10x+x equation: 



3/5x+5/2=1/10x+x

We move all terms to the left:

3/5x+5/2-(1/10x+x)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 10x+x)!=0

x∈R



We add all the numbers together, and all the variables

3/5x-(+x+1/10x)+5/2=0

We get rid of parentheses

3/5x-x-1/10x+5/2=0

We calculate fractions


250x^2/200x^2-x+120x/200x^2+(-20x)/200x^2=0

We add all the numbers together, and all the variables

250x^2/200x^2-1x+120x/200x^2+(-20x)/200x^2=0

We multiply all the terms by the denominator


250x^2-1x*200x^2+120x+(-20x)=0

We add all the numbers together, and all the variables

250x^2+120x-1x*200x^2+(-20x)=0

Wy multiply elements

250x^2-200x^3+120x+(-20x)=0

We get rid of parentheses

250x^2-200x^3+120x-20x=0

We do not support expression: x^3

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