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3/5x+5/3x=50
We move all terms to the left:
3/5x+5/3x-(50)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
9x/15x^2+25x/15x^2-50=0
We multiply all the terms by the denominator
9x+25x-50*15x^2=0
We add all the numbers together, and all the variables
34x-50*15x^2=0
Wy multiply elements
-750x^2+34x=0
a = -750; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·(-750)·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*-750}=\frac{-68}{-1500} =17/375 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*-750}=\frac{0}{-1500} =0 $
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