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3/5x+7=8+0.6x
We move all terms to the left:
3/5x+7-(8+0.6x)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-(0.6x+8)+7=0
We get rid of parentheses
3/5x-0.6x-8+7=0
We multiply all the terms by the denominator
-(0.6x)*5x-8*5x+7*5x+3=0
We add all the numbers together, and all the variables
-(+0.6x)*5x-8*5x+7*5x+3=0
We multiply parentheses
-0x^2-8*5x+7*5x+3=0
Wy multiply elements
-0x^2-40x+35x+3=0
We add all the numbers together, and all the variables
-1x^2-5x+3=0
a = -1; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·(-1)·3
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{37}}{2*-1}=\frac{5-\sqrt{37}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{37}}{2*-1}=\frac{5+\sqrt{37}}{-2} $
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