3/5x+7=x+1

Solution for 3/5x+7=x+1 equation:

3/5x+7=x+1

We move all terms to the left:

3/5x+7-(x+1)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We get rid of parentheses

3/5x-x-1+7=0

We multiply all the terms by the denominator


-x*5x-1*5x+7*5x+3=0

Wy multiply elements

-5x^2-5x+35x+3=0

We add all the numbers together, and all the variables

-5x^2+30x+3=0

a = -5; b = 30; c = +3;
Δ = b2-4ac
Δ = 302-4·(-5)·3
Δ = 960
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{960}=\sqrt{64*15}=\sqrt{64}*\sqrt{15}=8\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-8\sqrt{15}}{2*-5}=\frac{-30-8\sqrt{15}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+8\sqrt{15}}{2*-5}=\frac{-30+8\sqrt{15}}{-10}
$