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3/5x+x=600
We move all terms to the left:
3/5x+x-(600)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
x+3/5x-600=0
We multiply all the terms by the denominator
x*5x-600*5x+3=0
Wy multiply elements
5x^2-3000x+3=0
a = 5; b = -3000; c = +3;
Δ = b2-4ac
Δ = -30002-4·5·3
Δ = 8999940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8999940}=\sqrt{4*2249985}=\sqrt{4}*\sqrt{2249985}=2\sqrt{2249985}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3000)-2\sqrt{2249985}}{2*5}=\frac{3000-2\sqrt{2249985}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3000)+2\sqrt{2249985}}{2*5}=\frac{3000+2\sqrt{2249985}}{10} $
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