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3/5x-1-10x=12
We move all terms to the left:
3/5x-1-10x-(12)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-10x+3/5x-13=0
We multiply all the terms by the denominator
-10x*5x-13*5x+3=0
Wy multiply elements
-50x^2-65x+3=0
a = -50; b = -65; c = +3;
Δ = b2-4ac
Δ = -652-4·(-50)·3
Δ = 4825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4825}=\sqrt{25*193}=\sqrt{25}*\sqrt{193}=5\sqrt{193}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-5\sqrt{193}}{2*-50}=\frac{65-5\sqrt{193}}{-100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+5\sqrt{193}}{2*-50}=\frac{65+5\sqrt{193}}{-100} $
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