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3/5x-1/2x=13/20
We move all terms to the left:
3/5x-1/2x-(13/20)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
3/5x-1/2x-(+13/20)=0
We get rid of parentheses
3/5x-1/2x-13/20=0
We calculate fractions
(-260x^2)/400x^2+240x/400x^2+(-200x)/400x^2=0
We multiply all the terms by the denominator
(-260x^2)+240x+(-200x)=0
We get rid of parentheses
-260x^2+240x-200x=0
We add all the numbers together, and all the variables
-260x^2+40x=0
a = -260; b = 40; c = 0;
Δ = b2-4ac
Δ = 402-4·(-260)·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40}{2*-260}=\frac{-80}{-520} =2/13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40}{2*-260}=\frac{0}{-520} =0 $
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