If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(-9/4)*(-6/7)
8*x^3+32*x^2-(10*x)-40 = 0;x
x
(-1/3)^4
x^2*e^-x
cos(ln(x))
| 4[-3(2x+3)+5(5x-3)]= | | B*(c+88)= | | 4*(c+89)= | | y=(x+3)(2x-5) | | (-9/4)(-6/7) | | F(9a)=x+6 | | 6(-5x+7)=8(4x-6) | | f=3x^2+5 | | 99999999999999999999999999= | | 2x+2y-6x+5x^2-7y= | | 4x-24=-7x-28 | | 2m+m-(m-2)= | | 2(X-1)/5 | | 2tanx+9=0 | | 0.32+0.23(x-1)=19 | | 10=4a+3 | | 0.33+0.23(x-1)=19 | | 5x+8y=-7 | | (4x+3)(7x-5)= | | 4.4x-10.88=5.4 | | 0=0.04t^2+2t-200 | | 7x+2(6x+9)=170 | | 2x-5(x-3)=0 | | (36/5(5/14)/(-5/4) | | x/-4-3=7 | | 2/5×5 | | 3-8k=-125 | | f(-4)f(x)=x^2-3x+9 | | Y=-6/5x-12/5 | | 0=0.04(t^2-50t+5000) | | 0=12x^2-84x+80 | | A/a-b=-2/a-1 |