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3/5x-1/5x+2=12
We move all terms to the left:
3/5x-1/5x+2-(12)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-1/5x-10=0
We multiply all the terms by the denominator
-10*5x+3-1=0
We add all the numbers together, and all the variables
-10*5x+2=0
Wy multiply elements
-50x+2=0
We move all terms containing x to the left, all other terms to the right
-50x=-2
x=-2/-50
x=1/25
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