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3/5x-10=47
We move all terms to the left:
3/5x-10-(47)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-57=0
We multiply all the terms by the denominator
-57*5x+3=0
Wy multiply elements
-285x+3=0
We move all terms containing x to the left, all other terms to the right
-285x=-3
x=-3/-285
x=1/95
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