3/5x-16=41

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Solution for 3/5x-16=41 equation: 



3/5x-16=41

We move all terms to the left:

3/5x-16-(41)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We add all the numbers together, and all the variables

3/5x-57=0

We multiply all the terms by the denominator


-57*5x+3=0

Wy multiply elements

-285x+3=0

We move all terms containing x to the left, all other terms to the right

-285x=-3

x=-3/-285

x=1/95

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