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3/5x-1=1/x+1
We move all terms to the left:
3/5x-1-(1/x+1)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x+1)!=0We get rid of parentheses
x∈R
3/5x-1/x-1-1=0
We calculate fractions
3x/5x^2+(-5x)/5x^2-1-1=0
We add all the numbers together, and all the variables
3x/5x^2+(-5x)/5x^2-2=0
We multiply all the terms by the denominator
3x+(-5x)-2*5x^2=0
Wy multiply elements
-10x^2+3x+(-5x)=0
We get rid of parentheses
-10x^2+3x-5x=0
We add all the numbers together, and all the variables
-10x^2-2x=0
a = -10; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-10)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-10}=\frac{0}{-20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-10}=\frac{4}{-20} =-1/5 $
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