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x in (-oo:+oo)
(3/5)*x-((2/5)*(x-3)) = (1/5)*x+3 // - (1/5)*x+3
(3/5)*x-((2/5)*(x-3))-((1/5)*x)-3 = 0
(-2/5)*(x-3)+(3/5)*x+(-1/5)*x-3 = 0
(3*x)/5-2/5*(x-3)-x/5-3 = 0
(-2/5*5*(x-3))/5+(3*x)/5-x/5+(-3*5)/5 = 0
3*x-2/5*5*(x-3)-x-3*5 = 0
x-x-15+6 = 0
6-15 = 0
-9 = 0
-9/5 = 0
-9/5 = 0 // * 5
-9 = 0
x belongs to the empty set
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