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3/5x-4/3x=22/15
We move all terms to the left:
3/5x-4/3x-(22/15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
3/5x-4/3x-(+22/15)=0
We get rid of parentheses
3/5x-4/3x-22/15=0
We calculate fractions
(-990x^2)/225x^2+135x/225x^2+(-300x)/225x^2=0
We multiply all the terms by the denominator
(-990x^2)+135x+(-300x)=0
We get rid of parentheses
-990x^2+135x-300x=0
We add all the numbers together, and all the variables
-990x^2-165x=0
a = -990; b = -165; c = 0;
Δ = b2-4ac
Δ = -1652-4·(-990)·0
Δ = 27225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{27225}=165$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-165)-165}{2*-990}=\frac{0}{-1980} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-165)+165}{2*-990}=\frac{330}{-1980} =-1/6 $
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