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3/5x-6=2x+2
We move all terms to the left:
3/5x-6-(2x+2)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
3/5x-2x-2-6=0
We multiply all the terms by the denominator
-2x*5x-2*5x-6*5x+3=0
Wy multiply elements
-10x^2-10x-30x+3=0
We add all the numbers together, and all the variables
-10x^2-40x+3=0
a = -10; b = -40; c = +3;
Δ = b2-4ac
Δ = -402-4·(-10)·3
Δ = 1720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1720}=\sqrt{4*430}=\sqrt{4}*\sqrt{430}=2\sqrt{430}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{430}}{2*-10}=\frac{40-2\sqrt{430}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{430}}{2*-10}=\frac{40+2\sqrt{430}}{-20} $
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