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3/5x-7=12
We move all terms to the left:
3/5x-7-(12)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/5x-19=0
We multiply all the terms by the denominator
-19*5x+3=0
Wy multiply elements
-95x+3=0
We move all terms containing x to the left, all other terms to the right
-95x=-3
x=-3/-95
x=3/95
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