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3/5x=1/4x+200
We move all terms to the left:
3/5x-(1/4x+200)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 4x+200)!=0We get rid of parentheses
x∈R
3/5x-1/4x-200=0
We calculate fractions
12x/20x^2+(-5x)/20x^2-200=0
We multiply all the terms by the denominator
12x+(-5x)-200*20x^2=0
Wy multiply elements
-4000x^2+12x+(-5x)=0
We get rid of parentheses
-4000x^2+12x-5x=0
We add all the numbers together, and all the variables
-4000x^2+7x=0
a = -4000; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-4000)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-4000}=\frac{-14}{-8000} =7/4000 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-4000}=\frac{0}{-8000} =0 $
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