3/5x=4+2x

Solution for 3/5x=4+2x equation:

3/5x=4+2x

We move all terms to the left:

3/5x-(4+2x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

3/5x-(2x+4)=0

We get rid of parentheses

3/5x-2x-4=0

We multiply all the terms by the denominator


-2x*5x-4*5x+3=0

Wy multiply elements

-10x^2-20x+3=0

a = -10; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·(-10)·3
Δ = 520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{520}=\sqrt{4*130}=\sqrt{4}*\sqrt{130}=2\sqrt{130}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{130}}{2*-10}=\frac{20-2\sqrt{130}}{-20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{130}}{2*-10}=\frac{20+2\sqrt{130}}{-20}
$