3/5xx15=6/5x+12=

Solution for 3/5xx15=6/5x+12= equation:

3/5xx15=6/5x+12=

We move all terms to the left:

3/5xx15-(6/5x+12)=0


Domain of the equation: 5xx15!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 5x+12)!=0

x∈R


We get rid of parentheses

3/5xx15-6/5x-12=0

We calculate fractions


15x/25x^2+(-30x)/25x^2-12=0

We multiply all the terms by the denominator


15x+(-30x)-12*25x^2=0

Wy multiply elements

-300x^2+15x+(-30x)=0

We get rid of parentheses

-300x^2+15x-30x=0

We add all the numbers together, and all the variables

-300x^2-15x=0

a = -300; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·(-300)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*-300}=\frac{0}{-600}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*-300}=\frac{30}{-600}
=-1/20
$