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3/5y+2=1/2y
We move all terms to the left:
3/5y+2-(1/2y)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 2y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
3/5y-(+1/2y)+2=0
We get rid of parentheses
3/5y-1/2y+2=0
We calculate fractions
6y/10y^2+(-5y)/10y^2+2=0
We multiply all the terms by the denominator
6y+(-5y)+2*10y^2=0
Wy multiply elements
20y^2+6y+(-5y)=0
We get rid of parentheses
20y^2+6y-5y=0
We add all the numbers together, and all the variables
20y^2+y=0
a = 20; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·20·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*20}=\frac{-2}{40} =-1/20 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*20}=\frac{0}{40} =0 $
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