3/5y+32=12

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Solution for 3/5y+32=12 equation: 



3/5y+32=12

We move all terms to the left:

3/5y+32-(12)=0



Domain of the equation: 5y!=0

y!=0/5

y!=0

y∈R



We add all the numbers together, and all the variables

3/5y+20=0

We multiply all the terms by the denominator


20*5y+3=0

Wy multiply elements

100y+3=0

We move all terms containing y to the left, all other terms to the right

100y=-3

y=-3/100

y=-3/100

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