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3/5y-(y+9)=-12
We move all terms to the left:
3/5y-(y+9)-(-12)=0
Domain of the equation: 5y!=0We add all the numbers together, and all the variables
y!=0/5
y!=0
y∈R
3/5y-(y+9)+12=0
We get rid of parentheses
3/5y-y-9+12=0
We multiply all the terms by the denominator
-y*5y-9*5y+12*5y+3=0
Wy multiply elements
-5y^2-45y+60y+3=0
We add all the numbers together, and all the variables
-5y^2+15y+3=0
a = -5; b = 15; c = +3;
Δ = b2-4ac
Δ = 152-4·(-5)·3
Δ = 285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{285}}{2*-5}=\frac{-15-\sqrt{285}}{-10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{285}}{2*-5}=\frac{-15+\sqrt{285}}{-10} $
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