3/6(x-3)+10=2/4(3x-4)

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Solution for 3/6(x-3)+10=2/4(3x-4) equation: 



3/6(x-3)+10=2/4(3x-4)

We move all terms to the left:

3/6(x-3)+10-(2/4(3x-4))=0



Domain of the equation: 6(x-3)!=0

x∈R





Domain of the equation: 4(3x-4))!=0

x∈R



We calculate fractions


(12x3/(6(x-3)*4(3x-4)))+(-12xx/(6(x-3)*4(3x-4)))+10=0



We calculate terms in parentheses: +(12x3/(6(x-3)*4(3x-4))), so:

12x3/(6(x-3)*4(3x-4))

We multiply all the terms by the denominator


12x3

We add all the numbers together, and all the variables

12x^3

We do not support expression: x^3

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