3/7(14y-56)=-2y+16

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Solution for 3/7(14y-56)=-2y+16 equation: 



3/7(14y-56)=-2y+16

We move all terms to the left:

3/7(14y-56)-(-2y+16)=0



Domain of the equation: 7(14y-56)!=0

y∈R



We get rid of parentheses

3/7(14y-56)+2y-16=0

We multiply all the terms by the denominator


2y*7(14y-56)-16*7(14y-56)+3=0

Wy multiply elements

14y^2(1-112y(1+3=0

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