3/7(2x+4)=x-17

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Solution for 3/7(2x+4)=x-17 equation: 



3/7(2x+4)=x-17

We move all terms to the left:

3/7(2x+4)-(x-17)=0



Domain of the equation: 7(2x+4)!=0

x∈R



We get rid of parentheses

3/7(2x+4)-x+17=0

We multiply all the terms by the denominator


-x*7(2x+4)+17*7(2x+4)+3=0

Wy multiply elements

-7x^2(2+119x(2+3=0

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