3/7(7x-14)=12x+20

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Solution for 3/7(7x-14)=12x+20 equation: 



3/7(7x-14)=12x+20

We move all terms to the left:

3/7(7x-14)-(12x+20)=0



Domain of the equation: 7(7x-14)!=0

x∈R



We get rid of parentheses

3/7(7x-14)-12x-20=0

We multiply all the terms by the denominator


-12x*7(7x-14)-20*7(7x-14)+3=0

Wy multiply elements

-84x^2(7-140x(7+3=0

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