3/7(k+14)-k=6

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Solution for 3/7(k+14)-k=6 equation: 



3/7(k+14)-k=6

We move all terms to the left:

3/7(k+14)-k-(6)=0



Domain of the equation: 7(k+14)!=0

k∈R



We add all the numbers together, and all the variables

-1k+3/7(k+14)-6=0

We multiply all the terms by the denominator


-1k*7(k+14)-6*7(k+14)+3=0

Wy multiply elements

-7k^2(k-42k(k+3=0

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