3/7(x+1)=1/14(x+4)

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Solution for 3/7(x+1)=1/14(x+4) equation: 



3/7(x+1)=1/14(x+4)

We move all terms to the left:

3/7(x+1)-(1/14(x+4))=0



Domain of the equation: 7(x+1)!=0

x∈R





Domain of the equation: 14(x+4))!=0

x∈R



We calculate fractions


(42xx/(7(x+1)*14(x+4)))+(-7xx/(7(x+1)*14(x+4)))=0



We calculate terms in parentheses: +(42xx/(7(x+1)*14(x+4))), so:

42xx/(7(x+1)*14(x+4))

We multiply all the terms by the denominator


42xx

Back to the equation:

+(42xx)





We calculate terms in parentheses: +(-7xx/(7(x+1)*14(x+4))), so:

-7xx/(7(x+1)*14(x+4))

We multiply all the terms by the denominator


-7xx

Back to the equation:

+(-7xx)



We get rid of parentheses

42xx-7xx=0

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