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3/7(x+1)=1/28(x+3)
We move all terms to the left:
3/7(x+1)-(1/28(x+3))=0
Domain of the equation: 7(x+1)!=0
x∈R
Domain of the equation: 28(x+3))!=0We calculate fractions
x∈R
(84xx/(7(x+1)*28(x+3)))+(-7xx/(7(x+1)*28(x+3)))=0
We calculate terms in parentheses: +(84xx/(7(x+1)*28(x+3))), so:
84xx/(7(x+1)*28(x+3))
We multiply all the terms by the denominator
84xx
Back to the equation:
+(84xx)
We calculate terms in parentheses: +(-7xx/(7(x+1)*28(x+3))), so:We get rid of parentheses
-7xx/(7(x+1)*28(x+3))
We multiply all the terms by the denominator
-7xx
Back to the equation:
+(-7xx)
84xx-7xx=0
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