3/7(x+3)+1/6=1/3(7-5x)

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Solution for 3/7(x+3)+1/6=1/3(7-5x) equation: 



3/7(x+3)+1/6=1/3(7-5x)

We move all terms to the left:

3/7(x+3)+1/6-(1/3(7-5x))=0



Domain of the equation: 7(x+3)!=0

x∈R





Domain of the equation: 3(7-5x))!=0

x∈R



We add all the numbers together, and all the variables

3/7(x+3)-(1/3(-5x+7))+1/6=0

We calculate fractions


(54x(-)/(7(x+3)*3(-5x+7))*6)+(-(1*7(x+3)*6)/(7(x+3)*3(-5x+7))*6)+(21x^2x/(7(x+3)*3(-5x+7))*6)=0



We calculate terms in parentheses: +(54x(-)/(7(x+3)*3(-5x+7))*6), so:

54x(-)/(7(x+3)*3(-5x+7))*6

We add all the numbers together, and all the variables

54x0/(7(x+3)*3(-5x+7))*6

We multiply all the terms by the denominator


54x0

We add all the numbers together, and all the variables

54x

Back to the equation:

+(54x)





We calculate terms in parentheses: +(-(1*7(x+3)*6)/(7(x+3)*3(-5x+7))*6), so:

-(1*7(x+3)*6)/(7(x+3)*3(-5x+7))*6

We multiply all the terms by the denominator


-(1*7(x+3)*6)



We calculate terms in parentheses: -(1*7(x+3)*6), so:

1*7(x+3)*6

Wy multiply elements

42x(x

Back to the equation:

-(42x(x)



Back to the equation:

+(-(42xx)





We calculate terms in parentheses: +(21x^2x/(7(x+3)*3(-5x+7))*6), so:

21x^2x/(7(x+3)*3(-5x+7))*6

We multiply all the terms by the denominator


21x^2x

Back to the equation:

+(21x^2x)



determiningTheFunctionDomain
(-42xx+21x^2x+54x=0

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