3/7(x-2)+2x=5/2(x+3)

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Solution for 3/7(x-2)+2x=5/2(x+3) equation: 



3/7(x-2)+2x=5/2(x+3)

We move all terms to the left:

3/7(x-2)+2x-(5/2(x+3))=0



Domain of the equation: 7(x-2)!=0

x∈R





Domain of the equation: 2(x+3))!=0

x∈R



We add all the numbers together, and all the variables

2x+3/7(x-2)-(5/2(x+3))=0

We calculate fractions


2x+(6xx/(7(x-2)*2(x+3)))+(-35xx/(7(x-2)*2(x+3)))=0



We calculate terms in parentheses: +(6xx/(7(x-2)*2(x+3))), so:

6xx/(7(x-2)*2(x+3))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-35xx/(7(x-2)*2(x+3))), so:

-35xx/(7(x-2)*2(x+3))

We multiply all the terms by the denominator


-35xx

Back to the equation:

+(-35xx)



We get rid of parentheses

2x+6xx-35xx=0

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