3/7*y+4/148y=10

Solution for 3/7*y+4/148y=10 equation:

3/7y+4/148y=10

We move all terms to the left:

3/7y+4/148y-(10)=0


Domain of the equation: 7y!=0

y!=0/7

y!=0

y∈R



Domain of the equation: 148y!=0

y!=0/148

y!=0

y∈R


We calculate fractions


444y/1036y^2+28y/1036y^2-10=0

We multiply all the terms by the denominator


444y+28y-10*1036y^2=0

We add all the numbers together, and all the variables

472y-10*1036y^2=0

Wy multiply elements

-10360y^2+472y=0

a = -10360; b = 472; c = 0;
Δ = b2-4ac
Δ = 4722-4·(-10360)·0
Δ = 222784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{222784}=472$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(472)-472}{2*-10360}=\frac{-944}{-20720}
=59/1295
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(472)+472}{2*-10360}=\frac{0}{-20720}
=0
$