3/7/21/49=63/n

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Solution for 3/7/21/49=63/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

((3/7)/21)/49 = 63/n // - 63/n

((3/7)/21)/49-(63/n) = 0

((3/7)/21)/49-63*n^-1 = 0

-63*n^-1 = -1/2401 // : -63

n^-1 = 1/151263

-1 < 0

1/(n^1) = 1/151263 // * n^1

1 = 1/151263*n^1 // : 1/151263

151263 = n^1

n = 151263

n = 151263

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